An irregularly shaped object is attached to an axle so that it may be spun. If a torque of 250 N·m must be applied for 1.25 s in order to give it a rotation period of 0.10 s, what is its moment of inertia? A) 5.0 kg m² B) 31 kg m² C) 4.0 kg m² D) 25 kg m²

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Quizplus · Accepted Answer

The moment of inertia is given by I = T * t / w, where T is the torque, t is the time, and w is the angular velocity. In this case, T = 250 N·m, t = 1.25 s, and w = 2π / 0.10 s = 20π rad/s. Therefore, I = 250 N·m * 1.25 s / 20π rad/s = 5.0 kg m^2.

An Irregularly Shaped Object Is Attached to an Axle So